Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?O 1+ 21iO-1+ V19i1+2 V191iO 1+ V19i

The values of x are:1+√19i1-√19iStep-by-step explanation:Given equation is:[tex]x^2+20=2x\\x^2-2x+20=0\\Comparing\ with\ the\ standard\ form\ of\ quadratic\ equation\\ax^2+bx+c = 0\\a=1\\b=-2\\c=20Using Quadratic formula\\x = \frac{-b+\sqrt{b^2-4ac}}{2a}\ \ \ , x = \frac{-b-\sqrt{b^2-4ac}}{2a}\\x = \frac{-(-2)+\sqrt{(-2)^2-4(1)(20)}}{2(1)}\ \ \ , x = \frac{-(-2)-\sqrt{(-2)^2-4(1)(20)}}{2(1)}\\x = \frac{2+\sqrt{4-80)}}{2}\ \ \ , x = \frac{2-\sqrt{4-80)}}{2}\\x = \frac{2+\sqrt{-76)}}{2}\ \ \ , x = \frac{2-\sqrt{-76)}}{2}\\[/tex][tex]x = \frac{2+\sqrt{-19*4}}{2}\ \ \ , x = \frac{2-\sqrt{-19*4}}{2}\\x = \frac{2+\sqrt{-19*4}}{2}\ \ \ , x = \frac{2-\sqrt{-19*4}}{2}\\x = \frac{2+2\sqrt{-19}}{2}\ \ \ , x = \frac{2-2\sqrt{-19}}{2}\\x = \frac{2(1+\sqrt{-19})}{2}\ \ \ , x = \frac{2(1-\sqrt{-19})}{2}\\x = 1+\sqrt{-19}\ \ \ , x = 1-\sqrt{-19}\\\sqrt{-19} = \sqrt{19}*\sqrt{-1} \\As\ we\ know => \sqrt{-1} =i\\\sqrt{-19} = \sqrt{19}i\\So,\\x= 1+\sqrt{19}i\ \ \ \ , x=1-\sqrt{19}i[/tex]The values of x are:1+√19i1-√19iKeywords: Quadratic equation, value of variableLearn more about quadratic equation at:brainly.com/question/10364988brainly.com/question/10435816#LearnwithBrainly